Matematika Sekolah Menengah Atas tentukan nilai a, b, dan c, dari persamaan kuadrat!!!!

1) 4x²=7x
2) -6x²+10=7x+6
3) 2x (3x+5)=4
4) 5(x²+2)=2x(3x+1)

Mohon di jawab dgn lengkap....​

tentukan nilai a, b, dan c, dari persamaan kuadrat!!!!

1) 4x²=7x
2) -6x²+10=7x+6
3) 2x (3x+5)=4
4) 5(x²+2)=2x(3x+1)

Mohon di jawab dgn lengkap....​

Jawab:
(1.)   A = 4, B = -7, C = 0
(2.)  A = 6, B = 7, C = -4
(3.)  A = 6, B = 10, C = -4
(4.)  A = 1, B = 2, C = -10

Penjelasan:
Bentuk persamaan kuadrat
Ax² + Bx + C = 0

(1.) 4x² = 7x
4- 7x + 0 = 0
Ax² + Bx + C = 0
A = 4, B = -7, C = 0

(2.) -6x² + 10 = 7x + 6
6x² + 7x + 6 - 10 = 0
6x² + 7x - 4 = 0
Ax² + Bx + C = 0
A = 6, B = 7, C = -4

(3.) 2x(3x+5) = 4
2x(3x) + 2x(5) - 4 = 0
6x² + 10x - 4 = 0
Ax² + Bx + C = 0
A = 6, B = 10, C = -4

(4.) 5(x²+2) = 2x(3x+1)
5x² + 5(2) = 2x(3x) + 2x(1)
5x² + 10 = 6x² + 2x
6x²-5x² + 2x - 10 = 0
x² + 2x - 10 = 0
1x² + 2x - 10 = 0
Ax² + Bx + C = 0
A = 1, B = 2, C = -10

(xcvi)

Jawaban:

Bentuk Umum Persamaan Kuadrat

[tex] \boxed{ {ax}^{2} + bx + c = 0 }[/tex]

1. 4x² = 7x

4x² - 7x = 0

a = 4 b = -7 c = 0

2. -6x² + 10 = 7x + 6

-6x² -7x + 10 - 6 = 0

-6x² - 7x + 4 = 0

a = -6 b = -7 c = 4

3. 2x (3x + 5) = 4

6x² + 10x - 4 = 0

a = 6 b = 10 c = -4

4. 5(x² + 2) = 2x(3x + 1)

5x² + 10 = 6x² + 2x

5x² - 6x² - 2x + 10 = 0

-x² - 2x + 10 = 0

a = -1 b = -2x c = 10

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